Decades: 1250s 1260s 1270s 1280s 1290s - 1300s - 1310s 1320s 1330s 1340s 1350s
Years: 1295 1296 1297 1298 1299 - 1300 - 1301 1302 1303 1304 1305
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... get <math>x=\frac{-b}{2a}\pm\frac{\sqrt{b^2-4ac}}{2a}=\frac{-b\pm\sqrt{b^2-4ac}}{2a}.</math> Generalizations The formula and its proof remain correct ...