Centuries: 13th century - 14th century - 15th century
Decades: 1280s 1290s 1300s 1310s 1320s - 1330s - 1340s 1350s 1360s 1370s 1380s
Years: 1330 1331 1332 1333 1334 1335 1336 1337 1338 1339
... both sides, we get <math>x=\frac{-b}{2a}\pm\frac{\sqrt{b^2-4ac}}{2a}=\frac{-b\pm\sqrt{b^2-4ac}}{2a}.</math> Generalizations The formula and its ...