Centuries: 13th century - 14th century - 15th century
Decades: 1250s 1260s 1270s 1280s 1290s - 1300s - 1310s 1320s 1330s 1340s 1350s
Years: 1300 1301 1302 1303 1304 1305 1306 1307 1308 1309
... b/(2a) from both sides, we get <math>x=\frac{-b}{2a}\pm\frac{\sqrt{b^2-4ac}}{2a}=\frac{-b\pm\sqrt{b^2-4ac}}{2a}.</math> ...