Composers
Tango
Misc
Media
Tech
NL
LatAm/Peru
Food
Like to work on someday
... both sides, we get <math>x=\frac{-b}{2a}\pm\frac{\sqrt{b^2-4ac}}{2a}=\frac{-b\pm\sqrt{b^2-4ac}}{2a}.</math> Generalizations The formula and its ...