Centuries: 9th century - 10th century - 11th century
Decades: 870s - 880s - 890s - 900s - 910s - 920s - 930s - 940s - 950s - 960s -- 970s
Years: 920 921 922 923 924 925 926 927 928 929
... get <math>x=\frac{-b}{2a}\pm\frac{\sqrt{b^2-4ac}}{2a}=\frac{-b\pm\sqrt{b^2-4ac}}{2a}.</math> Generalizations The formula and its proof remain correct ...