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Years: 1265 1266 1267 1268 1269 - 1270 - 1271 1272 1273 1274 1275
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... we get <math>x=\frac{-b}{2a}\pm\frac{\sqrt{b^2-4ac}}{2a}=\frac{-b\pm\sqrt{b^2-4ac}}{2a}.</math> Generalizations The formula and its proof remain ...