Not to be forgotten:
Retired numbers:
Current stars:
Washington Wizards official web site (http://www.nba.com/wizards/)
... both sides, we get <math>x=\frac{-b}{2a}\pm\frac{\sqrt{b^2-4ac}}{2a}=\frac{-b\pm\sqrt{b^2-4ac}}{2a}.</math> Generalizations The formula and its ...