Articles I plan to work on eventually. Listing them here is primarily a reminder to me, not to discourage anyone else from working on them before I get around to it. -- Infrogmation
... we get
<math>x=\frac{-b}{2a}\pm\frac{\sqrt{b^2-4ac}}{2a}=\frac{-b\pm\sqrt{b^2-4ac}}{2a}.</math>
Generalizations
The formula and its proof remain ...