f [] = [] f (x:xs) = 1 : f xsis transformed into (pseudo C/Haskell):
f [] = []
f l = f' l allocate_cons
f' [] p = { *p = nil;
return *p
}
f' (x:xs) p = { cell = allocate_cons;
*p = cell;
cell.head = 1;
return f' xs &cell.tail
}
where allocate_cons returns the address of a new cons cell, *p is the location pointed to by p and &c is the address of c.
[D.H.D. Warren, DAI Research Report 141, University of Edinburgh 1980].
|
Search Encyclopedia
|
Featured Article
|