Howard, Brown County, Wisconsin

Geography Howard is located at 44°33'47" North, 88°4'55" West (44.563091, -88.081856)¹.

According to the United States Census Bureau, the village has a total area of 59.4 km² (22.9 mi²). 46.5 km² (18.0 mi²) of it is land and 12.9 km² (5.0 mi²) of it is water. The total area is 21.67% water.

Demographics As of the census of 2000, there are 13,546 people, 5,236 households, and 3,691 families residing in the village. The population density is 291.0/km² (753.7/mi²). There are 5,350 housing units at an average density of 114.9/km² (297.7/mi²). The racial makeup of the village is 96.16% White, 0.73% African American, 0.90% Native American, 0.78% Asian, 0.01% Pacific Islander, 0.32% from other races, and 1.10% from two or more races. 1.09% of the population are Hispanic or Latino of any race.

There are 5,236 households out of which 38.2% have children under the age of 18 living with them, 57.7% are married couples living together, 9.3% have a female householder with no husband present, and 29.5% are non-families. 21.7% of all households are made up of individuals and 6.0% have someone living alone who is 65 years of age or older. The average household size is 2.57 and the average family size is 3.04.

In the village the population is spread out with 27.8% under the age of 18, 8.6% from 18 to 24, 34.8% from 25 to 44, 21.3% from 45 to 64, and 7.5% who are 65 years of age or older. The median age is 34 years. For every 100 females there are 96.6 males. For every 100 females age 18 and over, there are 94.7 males.

The median income for a household in the village is $51,974, and the median income for a family is $56,579. Males have a median income of $40,081 versus $25,900 for females. The per capita income for the village is $21,688. 4.3% of the population and 3.2% of families are below the poverty line. Out of the total people living in poverty, 4.7% are under the age of 18 and 3.7% are 65 or older.