Clinton, Nebraska

Geography Clinton is located at 42°45'34" North, 102°20'55" West (42.759365, -102.348670)¹.

According to the United States Census Bureau, the village has a total area of 0.2 km² (0.1 mi²). 0.2 km² (0.1 mi²) of it is land and none of it is covered by water.

Demographics As of the census of 2000, there are 30 people, 16 households, and 11 families residing in the village. The population density is 128.7/km² (319.7/mi²). There are 17 housing units at an average density of 72.9/km² (181.1/mi²). The racial makeup of the village is 96.67% White, 0.00% African American, 0.00% Native American, 0.00% Asian, 0.00% Pacific Islander, 0.00% from other races, and 3.33% from two or more races. 0.00% of the population are Hispanic or Latino of any race.

There are 16 households out of which 6.3% have children under the age of 18 living with them, 56.3% are married couples living together, 12.5% have a female householder with no husband present, and 31.3% are non-families. 31.3% of all households are made up of individuals and 12.5% have someone living alone who is 65 years of age or older. The average household size is 1.88 and the average family size is 2.27.

In the village the population is spread out with 6.7% under the age of 18, 3.3% from 18 to 24, 26.7% from 25 to 44, 26.7% from 45 to 64, and 36.7% who are 65 years of age or older. The median age is 56 years. For every 100 females there are 100.0 males. For every 100 females age 18 and over, there are 100.0 males.

The median income for a household in the village is $40,000, and the median income for a family is $41,250. Males have a median income of $26,250 versus $22,500 for females. The per capita income for the village is $22,977. 0.0% of the population and 0.0% of families are below the poverty line.