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Decades: 900s BC 890s BC 880s BC 870s BC 860s BC - 850s BC - 840s BC 830s BC 820s BC 810s BC 800s BC
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... + \left( \frac{b}{a} \right) x + \frac{c}{a}=0 </math> which is equivalent to <math>x^2+\frac{b}{a}x=-\frac{c}{a}.</math> The equation is ...