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Decades: 900s BC 890s BC 880s BC 870s BC 860s BC - 850s BC - 840s BC 830s BC 820s BC 810s BC 800s BC
Significant People
... b/(2a) from both sides, we get <math>x=\frac{-b}{2a}\pm\frac{\sqrt{b^2-4ac}}{2a}=\frac{-b\pm\sqrt{b^2-4ac}}{2a}.</math> Generalizations The ...