Talk:Lagrange inversion theorem

<math>

  \left.
  g(z) = a
  + \sum_{n=1}^{\infty}
  \frac{d^{n-1}}{(dw)^{n-1}}
  \left( \frac{(w-a)^n}{(f(w) - b)^n} \right)
  \right|
  _{w = a}
  {\frac{(z - b)^n}{n!}}

                 ∞    dn-1  /  (w - a)n    \ |      (z - b)n 
    g(z) = a  +  ∑  ------ | -----------  | |      --------                      
                n=1 (dw)n-1 \ (f(w) - b)n  / |         n!
                                            | w=a

--Edmund 02:23 Feb 22, 2003 (UTC)

Yup, the TeX is correct now. AxelBoldt 20:45 Mar 2, 2003 (UTC)