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Talk:Chaitin's constant

... then there exists a constant N such that no digit of Ů after the N-th can be proven to be one or zero within that system.

Is this true? It seems like this states that there are at most a finite number of Turing machines that can be proven to either halt or not halt (given some system of enumeration, etc.). Chas zzz brown 02:06 Feb 5, 2003 (UTC)

Ooops! In the words of emily latella, "never mind". I misread that the nth digit of Ω was 1 iff Turing machine n halts. Chas zzz brown 09:00 Feb 5, 2003 (UTC)b



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