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RFC 1812

An RFC from the IETF,



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Quadratic formula

... get <math>x=\frac{-b}{2a}\pm\frac{\sqrt{b^2-4ac}}{2a}=\frac{-b\pm\sqrt{b^2-4ac}}{2a}.</math> Generalizations The formula and its proof remain correct ...

 
 
 
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