For example, there must be at least two people in London with the same number of hairs on their heads. Demonstration: a typical head of hair has around 150,000 hairs. It is reasonable to assume that no-one has more than 1,000,000 hairs on their head. There are more than 1,000,000 people in London. If we assign a pigeonhole for each number of hairs on a head, and assign people to the pigeonhole with their number of hairs on it, there must be two people with the same number of hairs on their heads.
A generalized version of this principle states that, if n discrete objects are to be allocated to m containers, then at least one container must hold no fewer than <math>\lceil n/m \rceil</math> objects, where <math>\lceil\dots\rceil</math> denotes the ceiling function.
The pigeonhole principle is an example of a counting argument[?] which can be applied to many more serious problems, including ones involving infinite sets that cannot be put into one-to-one correspondence.
See also: cardinal number
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