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North Roseau, Minnesota

North Roseau is an unorganized territory located in Roseau County, Minnesota. As of the 2000 census, the unorganized territory had a total population of 160.

Geography According to the United States Census Bureau, the unorganized territory has a total area of 310.2 km² (119.8 mi²). 310.2 km² (119.8 mi²) of it is land and 0.01% is water.

Demographics As of the census of 2000, there are 160 people, 55 households, and 47 families residing in the unorganized territory. The population density is 0.5/km² (1.3/mi²). There are 65 housing units at an average density of 0.2/km² (0.5/mi²). The racial makeup of the unorganized territory is 98.12% White, 0.00% African American, 0.00% Native American, 1.25% Asian, 0.00% Pacific Islander, 0.00% from other races, and 0.62% from two or more races. 0.00% of the population are Hispanic or Latino of any race.

There are 55 households out of which 45.5% have children under the age of 18 living with them, 70.9% are married couples living together, 7.3% have a female householder with no husband present, and 14.5% are non-families. 12.7% of all households are made up of individuals and 5.5% have someone living alone who is 65 years of age or older. The average household size is 2.91 and the average family size is 3.17.

In the unorganized territory the population is spread out with 30.0% under the age of 18, 6.9% from 18 to 24, 28.8% from 25 to 44, 21.3% from 45 to 64, and 13.1% who are 65 years of age or older. The median age is 37 years. For every 100 females there are 105.1 males. For every 100 females age 18 and over, there are 115.4 males.

The median income for a household in the unorganized territory is $43,750, and the median income for a family is $44,583. Males have a median income of $31,528 versus $20,972 for females. The per capita income for the unorganized territory is $18,447. 0.0% of the population and 0.0% of families are below the poverty line.



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