External links
Kish (Ukhaimir) at The History of the Ancient Near East - http://ancientneareast.tripod.com/Kish_Ukhaimir
... get <math>\left(x+\frac{b}{2a}\right)^2=\frac{-4ac+b^2}{4a^2}=\frac{b^2-4ac}{4a^2}.</math> Taking square roots of bo ...