He was responsible for the Temple of Athena Nike, also on the Acropolis.
See also: Iktinos
... sides, we get <math>x=\frac{-b}{2a}\pm\frac{\sqrt{b^2-4ac}}{2a}=\frac{-b\pm\sqrt{b^2-4ac}}{2a}.</math> Generalizations The formula and its proof ...