Jefferson Heights, New York

Geography Jefferson Heights is located at 42°14'7" North, 73°52'34" West (42.235394, -73.876021)¹.

According to the United States Census Bureau, the town has a total area of 3.9 km² (1.5 mi²). 3.8 km² (1.5 mi²) of it is land and 0.1 km² (0.04 mi²) of it is water. The total area is 1.34% water.

Demographics As of the census of 2000, there are 1,104 people, 382 households, and 241 families residing in the town. The population density is 290.0/km² (752.3/mi²). There are 415 housing units at an average density of 109.0/km² (282.8/mi²). The racial makeup of the town is 95.74% White, 2.26% African American, 0.00% Native American, 1.27% Asian, 0.00% Pacific Islander, 0.09% from other races, and 0.63% from two or more races. 1.00% of the population are Hispanic or Latino of any race.

There are 382 households out of which 23.3% have children under the age of 18 living with them, 50.8% are married couples living together, 8.6% have a female householder with no husband present, and 36.9% are non-families. 34.3% of all households are made up of individuals and 15.7% have someone living alone who is 65 years of age or older. The average household size is 2.23 and the average family size is 2.80.

In the town the population is spread out with 16.1% under the age of 18, 4.8% from 18 to 24, 19.5% from 25 to 44, 19.8% from 45 to 64, and 39.8% who are 65 years of age or older. The median age is 55 years. For every 100 females there are 69.6 males. For every 100 females age 18 and over, there are 66.8 males.

The median income for a household in the town is $43,750, and the median income for a family is $45,365. Males have a median income of $47,109 versus $22,031 for females. The per capita income for the town is $17,321. 7.5% of the population and 2.6% of families are below the poverty line. Out of the total people living in poverty, 0.0% are under the age of 18 and 16.0% are 65 or older.