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Image:Aldrin near Module leg.jpg

Astronaut Edwin E. Aldrin near a leg of the Lunar Module, PD NASA photo

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... b/(2a) from both sides, we get <math>x=\frac{-b}{2a}\pm\frac{\sqrt{b^2-4ac}}{2a}=\frac{-b\pm\sqrt{b^2-4ac}}{2a}.</math> Generalizations ...