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Farson, Wyoming

Farson is a town located in Sweetwater County, Wyoming. As of the 2000 census, the town had a total population of 242.

Geography Farson is located at 42°10'19" North, 109°25'12" West (42.171927, -109.420096)1.

According to the United States Census Bureau, the town has a total area of 201.4 km² (77.8 mi²). 195.4 km² (75.4 mi²) of it is land and 6.1 km² (2.3 mi²) of it is water. The total area is 3.02% water.

Demographics As of the census of 2000, there are 242 people, 96 households, and 69 families residing in the town. The population density is 1.2/km² (3.2/mi²). There are 118 housing units at an average density of 0.6/km² (1.6/mi²). The racial makeup of the town is 96.28% White, 0.83% African American, 0.00% Native American, 0.00% Asian, 0.00% Pacific Islander, 1.65% from other races, and 1.24% from two or more races. 5.37% of the population are Hispanic or Latino of any race.

There are 96 households out of which 30.2% have children under the age of 18 living with them, 64.6% are married couples living together, 5.2% have a female householder with no husband present, and 28.1% are non-families. 26.0% of all households are made up of individuals and 9.4% have someone living alone who is 65 years of age or older. The average household size is 2.52 and the average family size is 3.01.

In the town the population is spread out with 23.6% under the age of 18, 8.7% from 18 to 24, 25.2% from 25 to 44, 31.8% from 45 to 64, and 10.7% who are 65 years of age or older. The median age is 40 years. For every 100 females there are 103.4 males. For every 100 females age 18 and over, there are 110.2 males.

The median income for a household in the town is $44,545, and the median income for a family is $56,806. Males have a median income of $41,364 versus $21,250 for females. The per capita income for the town is $16,140. 0.0% of the population and 0.0% of families are below the poverty line.

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