Coleharbor, North Dakota

Geography Coleharbor is located at 47°32'33" North, 101°13'23" West (47.542416, -101.223145)¹.

According to the United States Census Bureau, the city has a total area of 0.5 km² (0.2 mi²). 0.5 km² (0.2 mi²) of it is land and none of the area is covered with water.

Demographics As of the census of 2000, there are 106 people, 42 households, and 30 families residing in the city. The population density is 227.4/km² (581.2/mi²). There are 56 housing units at an average density of 120.1/km² (307.0/mi²). The racial makeup of the city is 98.11% White, 0.00% African American, 0.94% Native American, 0.00% Asian, 0.00% Pacific Islander, 0.00% from other races, and 0.94% from two or more races. 0.00% of the population are Hispanic or Latino of any race.

There are 42 households out of which 31.0% have children under the age of 18 living with them, 64.3% are married couples living together, 9.5% have a female householder with no husband present, and 26.2% are non-families. 21.4% of all households are made up of individuals and 9.5% have someone living alone who is 65 years of age or older. The average household size is 2.52 and the average family size is 2.94.

In the city the population is spread out with 25.5% under the age of 18, 7.5% from 18 to 24, 24.5% from 25 to 44, 26.4% from 45 to 64, and 16.0% who are 65 years of age or older. The median age is 43 years. For every 100 females there are 130.4 males. For every 100 females age 18 and over, there are 113.5 males.

The median income for a household in the city is $33,750, and the median income for a family is $40,313. Males have a median income of $27,000 versus $13,750 for females. The per capita income for the city is $13,845. 12.1% of the population and 6.9% of families are below the poverty line. Out of the total people living in poverty, 15.4% are under the age of 18 and 0.0% are 65 or older.