Camp Crook, South Dakota

Geography Camp Crook is located at 45°32'59" North, 103°58'31" West (45.549727, -103.975307)¹.

According to the United States Census Bureau, the town has a total area of 0.4 km² (0.1 mi²). 0.4 km² (0.1 mi²) of it is land and none of the area is covered with water.

Demographics As of the census of 2000, there are 56 people, 28 households, and 15 families residing in the town. The population density is 154.4/km² (406.4/mi²). There are 51 housing units at an average density of 140.7/km² (370.1/mi²). The racial makeup of the town is 98.21% White, 0.00% African American, 1.79% Native American, 0.00% Asian, 0.00% Pacific Islander, 0.00% from other races, and 0.00% from two or more races. 0.00% of the population are Hispanic or Latino of any race.

There are 28 households out of which 21.4% have children under the age of 18 living with them, 46.4% are married couples living together, 10.7% have a female householder with no husband present, and 42.9% are non-families. 39.3% of all households are made up of individuals and 7.1% have someone living alone who is 65 years of age or older. The average household size is 2.00 and the average family size is 2.69.

In the town the population is spread out with 19.6% under the age of 18, 3.6% from 18 to 24, 26.8% from 25 to 44, 44.6% from 45 to 64, and 5.4% who are 65 years of age or older. The median age is 45 years. For every 100 females there are 93.1 males. For every 100 females age 18 and over, there are 87.5 males.

The median income for a household in the town is $31,875, and the median income for a family is $33,750. Males have a median income of $29,375 versus $21,875 for females. The per capita income for the town is $30,178. 17.1% of the population and 18.2% of families are below the poverty line. Out of the total people living in poverty, 33.3% are under the age of 18 and 0.0% are 65 or older.