Arvin, California

Geography Arvin is located at 35°12'17" North, 118°49'56" West (35.204638, -118.832194)¹.

According to the United States Census Bureau, the city has a total area of 12.5 km² (4.8 mi²). 12.5 km² (4.8 mi²) of it is land and none of it is covered by water.

Demographics As of the census of 2000, there are 12,956 people, 3,010 households, and 2,645 families residing in the city. The population density is 1,040.0/km² (2,695.9/mi²). There are 3,145 housing units at an average density of 252.5/km² (654.4/mi²). The racial makeup of the city is 45.04% White, 1.08% African American, 1.46% Native American, 1.10% Asian, 0.12% Pacific Islander, 46.55% from other races, and 4.65% from two or more races. 87.53% of the population are Hispanic or Latino of any race.

There are 3,010 households out of which 63.2% have children under the age of 18 living with them, 67.7% are married couples living together, 13.7% have a female householder with no husband present, and 12.1% are non-families. 9.5% of all households are made up of individuals and 5.4% have someone living alone who is 65 years of age or older. The average household size is 4.28 and the average family size is 4.51.

In the city the population is spread out with 40.0% under the age of 18, 12.8% from 18 to 24, 28.8% from 25 to 44, 12.5% from 45 to 64, and 5.8% who are 65 years of age or older. The median age is 23 years. For every 100 females there are 111.0 males. For every 100 females age 18 and over, there are 108.3 males.

The median income for a household in the city is $23,674, and the median income for a family is $24,816. Males have a median income of $20,506 versus $17,684 for females. The per capita income for the city is $7,408. 32.6% of the population and 30.9% of families are below the poverty line. Out of the total people living in poverty, 37.6% are under the age of 18 and 23.1% are 65 or older.