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This article was originally based on material from FOLDOC, used with permission. Update as needed.
... y = b/(2a), so we add the square of b/(2a) to both sides, getting <math>x^2+\frac{b}{a}x+\frac{b^2}{4a^2}=-\frac{c}{a}+\frac{b^2}{4a^2}.</math> The left ...