(3rd millennium BC - 2nd millennium BC - 1st millennium BC)
Significant persons:
Inventions, Discoveries, Introductions:
... from both sides, we get <math>x=\frac{-b}{2a}\pm\frac{\sqrt{b^2-4ac}}{2a}=\frac{-b\pm\sqrt{b^2-4ac}}{2a}.</math> Generalizations The formula and ...