Decades: 1630s BC 1620s BC 1610s BC 1600s BC 1590s BC - 1580s BC - 1570s BC 1560s BC 1550s BC 1540s BC 1530s BC
Significant People
... of b/(2a) to both sides, getting <math>x^2+\frac{b}{a}x+\frac{b^2}{4a^2}=-\frac{c}{a}+\frac{b^2}{4a^2}.</math> The left side is now a perfect square; it ...