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# 1100s BC

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Centuries: 13th century BC - 12th century BC - 11th century BC

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 Quadratic formula ... of b/(2a) to both sides, getting $x^2+\frac{b}{a}x+\frac{b^2}{4a^2}=-\frac{c}{a}+\frac{b^2}{4a^2}.$ The left side is now a perfect square; ...