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Decades: 1150s BC 1140s BC 1130s BC 1120s BC 1110s BC - 1100s BC - 1090s BC 1080s BC 1070s BC 1060s BC 1050s BC
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... of b/(2a) to both sides, getting <math>x^2+\frac{b}{a}x+\frac{b^2}{4a^2}=-\frac{c}{a}+\frac{b^2}{4a^2}.</math> The left side is now a perfect square; ...